In rectangle ABCD, base AD = 8 cm and perpendicular height from vertex E to AD is 10 cm. The area of triangle ADE is (1/2) x base x height = (1/2) x 8 x 10 = 40 cm².
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In rectangle ABCD, base AD = 8 cm and perpendicular height from vertex E to AD is 10 cm. The area of triangle ADE is (1/2) x base x height = (1/2) x 8 x 10 = 40 cm².
From rectangle ABCD shown in Fig. 6.31, side AD = BC = 8 cm and side AB = CD = 10 cm.
For triangle ADE, take side AD as the base:
Base = AD = 8 cm.
Vertex E lies on the opposite side BC. The perpendicular distance from E to AD equals the width of the rectangle, which is CD = 10 cm.
Height = 10 cm.
Area of triangle ADE = (1/2) x base x height = (1/2) x 8 x 10 = 40 cm².
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/