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Home/ Questions/Q 207564
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manglu99
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manglu99
Asked: February 23, 20232023-02-23T08:45:19+00:00 2023-02-23T08:45:19+00:00In: Class 10 Maths

Find the area of the shaded region.

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Find the area of the shaded region.

In Figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter.
Class 10 maths NCERT chapter 12 AREAS RELATED TO CIRCLES
Page No. 237
Exercise 12.3
Question No. 15

chapter 12class 10ncert maths
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      Rocky Singh
      2023-02-24T06:29:28+00:00Added an answer on February 24, 2023 at 6:29 am
      Find the area of the shaded region.

      Radius of sector 14 cm
      Area of sector
      = 90°/360° × πr² = 1/4 × πr²
      = 1/4 × 22/7 × 14 × 14 = 154 cm²
      In AABC,
      BC² AC² + AB² ⇒ BC² = (14)² + (14)² ⇒ BC² = 196 + 196
      ⇒ BC² = 39² ⇒ BC = √392 ⇒ BC = 14√2
      Therefore, the diameter of semicircle = BC = 14√2
      Radius of semicircle = 7√2 cm
      Area of semicircle
      = 1/2 × πr² = 1/2 × π(7√2)² = 1/2 × 22/7 × 7√2 × 7√2 = 154 cm²
      Area of triangle ABC
      = 1/2 × AB × BC = 1/2 × 14 × 14 = 98 cm²
      Area of shaded region
      = Aera of triangle ABC + Area of semicircle – Area of quadrant
      = (98 + 154 – 154) cm²
      = 98 cm²

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