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Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 cm

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Boost your preparation for Class 9th Maths using NCERT solutions and MCQ-based questions from Chapter 10: Heron’s Formula. Practice exercise questions, short-answer problems and clear explanations to master concepts like semi-perimeter, area of triangles and its application to irregular quadrilaterals. These resources are designed as per the CBSE syllabus for effective exam readiness. Consistent practice will sharpen your logical reasoning and prepare you for board exams. Utilize step-by-step solutions and revision notes crafted for success.

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  1. Sides: 8 cm, 11 cm, 13 cm
    Perimeter = 32 cm → Semi-perimeter (s) = 16 cm

    Area = √[s(s-a)(s-b)(s-c)]
    = √[16(16-8)(16-11)(16-13)]
    = √[16 × 8 × 5 × 3]
    = √1920
    = 8√30 cm²
    This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions/class-9/maths/

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