Circumference 2 x (22/7) x r = 66 gives radius r = 21/2 cm. The area of the quadrant is (1/4) x π x r² = (1/4) x (22/7) x (21/2)² = 693/8 = 86.625 cm².
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Circumference of the circle = 2 x π x r = 66 cm.
Using π = 22/7:
2 x (22/7) x r = 66
(44/7) x r = 66
r = (66 x 7) / 44 = (3 x 7) / 2 = 21/2 cm = 10.5 cm.
A quadrant has a central angle of 90°.
Area of a quadrant = (1/4) x π x r²
= (1/4) x (22/7) x (21/2) x (21/2)
= (1/4) x 11 x 3 x (21/2) = 693 / 8 = 86.625 cm².
Hence, the area of the quadrant is 86.625 cm².
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/