NCERT Solutions for Class 8 Mathematics Chapter 14
Important NCERT Questions
Factorization Chapter 8 Exercise 14.2
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 2
Factorize the following expressions: (i) a²+8a+16 (ii) p²-10p+25
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(i) a²+8a+16 = a²+(4+4)a+4X4
Using identity x²+(a+b)x+ab=(x+a)(x+b),
Here x=a,a=4 and b=4
a²+8a+16 = (a+4)(a+4)=(a+4)²
(ii) p²-10p+25 = p²+(-5-5)p+(-5)(-5)
Using identity x²+(a+b)x+ab=(x+a)(x+b),
Here x=p,a=-5and b=-5
Class 8 Maths Chapter 11 Exercise 14.2 Solution in Video
for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/