(i) a²+8a+16 = a²+(4+4)a+4X4
Using identity x²+(a+b)x+ab=(x+a)(x+b),
Here x=a,a=4 and b=4
a²+8a+16 = (a+4)(a+4)=(a+4)²
(ii) p²-10p+25 = p²+(-5-5)p+(-5)(-5)
Using identity x²+(a+b)x+ab=(x+a)(x+b),
Here x=p,a=-5and b=-5

Class 8 Maths Chapter 11 Exercise 14.2 Solution in Video

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https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/