(i) 4p²-9p² = (2p)²-(3q)²
= (2p-3q)(2p+3q) [∵ a²-b²=(a-b)(a+b)]
(ii) 63a²-112b² =7(9a²-16b²)= 7[(3a)²-(4b)²]
= 7(3a-4b)(3a+4b) [∵ a²-b²=(a-b)(a+b)]

Class 8 Maths Chapter 11 Exercise 14.2 Solution in Video

for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/