Following the hint in the book, we factor out 1/3 as a common factor. This leaves the expression 9a square + 12ab + 4b square inside brackets, which factors into (3a + 2b) square.
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For this problem, we take out a fractional common factor to make the terms perfect integers. Factoring out 1/3 transforms the expression into 1/3 times the quantity 9a square + 12ab + 4b square. Inside the brackets, 9a square is the square of 3a, and 4b square is the square of 2b. The middle term is two times 3a times 2b. This simplifies perfectly to 1/3 times (3a + 2b) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/