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Home/ Questions/Q 209500
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Mridul Gupta
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Mridul Gupta
Asked: February 28, 20232023-02-28T09:31:18+00:00 2023-02-28T09:31:18+00:00In: Class 10 Maths

During the medical check-up of 35 students of a class, their weights were recorded as follows:

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During the medical check-up of 35 students of a class, their weights were recorded as follows:

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.
NCERT Math’s class 10 chapter 14
Page No. 293
Exercise 14.4
Question 2

chapter 14class 10ncert
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      Lalit gandhi
      2023-02-28T09:40:51+00:00Added an answer on February 28, 2023 at 9:40 am
      During the medical check-up of 35 students of a class, their weights were recorded as follows:

      It can be observed that the difference between two consecutive upper class limits is 2. The class marks with their respective frequencies are obtained as below.

      Weight (in kg) Less than38 38-40 40-42 42-44 44 46 46-48 48-50 50-52 Total(n)
      Frequency (f) 0 3-0=3 5-3=2 9-5=4 14-9=5 28-14=14 32-28=4 35-32=3 35
      Cumulative
      frequency 0 3 5 9 14 28 32 35

      The cumulative frequency just greater than n/2 (i.e. 35/2 = 17.5) is 28, belonging to class intervals 46- 48.
      Median class = 46 – 48
      lower class limit (l) of median class = 46
      Cumulative frequency (cf) of class preceding median class = 14
      Class size (h) = 2
      Median = l + ((n/2 – cf)/f) × h = 46 + ((17.5 – 14)/14) × 2 = 46 + 0.5 = 46.5
      Therefore, median of this data is 46.5.
      Hence, the value of median is verified.

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