NCERT Solutions for Class 6 Maths Chapter 3
Important NCERT Questions
Playing With Numbers Chapter 3 Exercise 3.7
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 4
Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12.
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Hints:-
L.C.M. of 6, 8 and 12 = 2 x 2 x 2 x 3 = 24
The smallest 3-digit number = 100
To find the number, we have to divide 100 by 24
100 = 24 x 4 + 4
Therefore, the required number = 100 + (24 – 4) = 120.
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