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Virat
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Asked: 2026-09-09T07:26:08+00:00 In:

Determine the AP whose third term is 16 and whose 7th term exceeds the 5th term by 12.

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Since t7 – t5 = 12, we have 2d = 12, giving d = 6. With third term a + 2d = 16, substituting d gives a = 4. The required AP is 4, 10, 16, 22, ….

ap whose third term is 16cbse class 9 ganita manjari chapter 8 solutionsclass 9 ganita manjari chapter 8 question answerncert solutions – predicting what comes next: exploring sequences and progressionswhose 7th term exceeds the 5th term by 12
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    1. Let the first term be a and common difference be d.

      Given:

      t7 – t5 = 12

      (a + 6d) – (a + 4d) = 12

      2d = 12

      d = 6.

      Also, the third term is 16:

      t3 = a + 2d = 16

      a + 2 x 6 = 16

      a + 12 = 16

      a = 4.

       

      With first term a = 4 and common difference d = 6, the terms are:

      First term = 4

      Second term = 4 + 6 = 10

      Third term = 10 + 6 = 16

      Fourth term = 16 + 6 = 22.

      Thus, the arithmetic progression is 4, 10, 16, 22, ….

       

      For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/

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