Daniel is paining the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m² of area is painted. How many cans of paint will she need to paint the room?

Here,
Length of wall (l) = 15 m, Breadth of wall (b) = 10 m and Height of wall (h) = 7 m
∴ Total Surface area of classroom = lb + 2(bh+hl)
= 15 x 10 + 2 (10 x 7 + 7 x 15)
= 150 + 2 (70 + 105) = 150 + 350 = 500 m²
Now Required number of cans = Area of hall/Area of one can =500/100=5cms
Hence, 5 cans are required to paint the room.

Class 8 Maths Chapter 11 Exercise 11.3 Solution in Video

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