Currents of 10 A and 2 A are flowing in opposite directions through two parallel wires A and B respectively. If the wire A is infinitely long and wire B is 2 m long, then force on wire B which is situated at 10 cm from A, is
The magnetic force per unit length between two parallel currents is given by:
F/L = μ0I₁ I₂/2πd
Substituting values (I = 10 A, I₂ = 2 A, d = 0.1 m):
F/L = 4π ×10⁻⁷ × 10 × 2/2π × 0.1 = 4 × 10⁻⁵ N/m
For 2 m length:
F = 4 × 10⁻⁵ × 2 = 8 × 10⁻⁵ N
Answer: (A) 8 × 10⁻⁵ N.
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The magnetic force per unit length between two parallel currents is given by:
F/L = μ0I₁ I₂/2πd
Here, I₁ = 10 A, I₂ = 2 A, d = 0.1 m: Substituting values:
F/L = (4π ×10⁻⁷)
(10) (2)/2π (0.1) = 4 × 10⁻⁵ N/m
For 2 m length of wire B, the total force is:
F = 4 × 10⁻⁵ × 2 = 8 × 10⁻⁵ N
Answer: (A) 8 × 10⁻⁵ N.
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