NCERT Solutions for Class 10 Maths Chapter 11

Important NCERT Questions

Constructions

NCERT Books for Session 2022-2023

CBSE Board and UP Board Others state Board

EXERCISE 11.2

Page No:220

Questions No:2

# Construct a tangent to a circle of radius 4 cm from a point on the concentric circle of radius 6 cm and measure its length. Also verify the measurement by actual calculation.

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Tangents on the given circle can be drawn as follow.

Step 1

Draw a circle of 4 cm radius with centre as O on the given plane.

Step 2 Draw a circle of 6 cm radius taking O as its centre. Locate a point P on this circle a join OP.

Step 3

Bisect OP. Let M be the mid-point of PO.

Step 4

Taking M as its centre and MO as Its radius, draw a circle. Let it intersect the given circle at the points Q and R.

Step 5

Join PQ and PR. PQ and PR are the required tangents.

It can be observed that PQ and PR are of length 4.47 cm each.

In ΔPQO,

since PQ is a tangent,

∠PQO = 90°

PO = 6 cm

QO = 4 CM

Applying Pythagoras theorem in ΔPQO, we obtain

PQ² + QO² = PQ² ⇒ PQ² + (4)² = (6)² ⇒ PQ² + 16 = 36

PQ² = 36 – 16 ⇒ PQ² = 20 ⇒ PQ = 2√5

PQ = 4.47 cm

Justification

The construction can be justified by proving that PQ and PR are the tangents to the circle (whose centre is O and radius is 4 cm). For this, let us join OQ and OR.

∠PQO is an angle in the semi- circle. We know that angle in a semi-circle is a right angle.

∴ ∠PQO = 90° ⇒ OQ ⊥PQ

Since OQ is the radius of the circle, PQ has to be a tangent of the circle. Similarly, PR is a tangent of the circle.