Garinder
  • 6

Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

  • 6

NCERT Solutions for Class 7 Mathematics Chapter 10
Important NCERT Questions
Class vii Math Chapter 10 Practical Geometry Exercise 10.3
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 1

Share

1 Answer

  1. To construct: ∆DEF where DE = 5 cm, DF = 3 cm and m∠EDF = 90°.
    Steps of construction: (a) Draw a line segment DF = 3 cm.
    (b) At point D, draw an angle 90° of with the help of compass i.e., ∠XDF = 90°.
    (c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E.
    (d) Join EF.
    It is the required right angled triangle DEF.

    Class 7 Maths Chapter 10 Exercise 10.3

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/

    • 4
Leave an answer

Leave an answer

Browse