In ∆BAT and ∆BAC, given triangles are congruent so the corresponding parts are:
B ↔ B, A ↔ A, T ↔ C
Thus, ∆BCA ≅ ∆BTA [By SSS congruence rule]
In ∆QRS and ∆TPQ, given triangles are congruent so the corresponding parts are:
P ↔ R, T ↔ Q, Q ↔ S
Thus, ∆QRS ≅ ∆TPQ [By SSS congruence rule]

Class 7 Maths Chapter 7 Exercise 7.2

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