To express sin A, sec A, and cot A in terms of cot A, we can use the above definitions and the relationship cot A = A/O:
Sin A = O/H = (O/A) * (A/H) = (1/cot A) * (1/sec A) = 1/(cot A * sec A)
Sec A = H/A = (H/O) * (O/A) = (1/sin A) * (1/cot A) = 1/(sin A * cot A)
Cot A = A/O = (A/H) * (H/O) = (sec A * sin A) * (1/cot A) = sec A * sin A
To express sin A, sec A, and cot A in terms of cot A, we can use the above definitions and the relationship cot A = A/O:
Sin A = O/H = (O/A) * (A/H) = (1/cot A) * (1/sec A) = 1/(cot A * sec A)
Sec A = H/A = (H/O) * (O/A) = (1/sin A) * (1/cot A) = 1/(sin A * cot A)
Cot A = A/O = (A/H) * (H/O) = (sec A * sin A) * (1/cot A) = sec A * sin A
For class 10 math Exercise 8.4 solutions click here =>
https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-8/exercise-8-4/