Changing the last two digits to 56 makes the number divisible by 8. For example, 8556 is a multiple of 8 because 8556 ÷ 8 = 1069 with no remainder.
Class 6 NCERT Ganita Prakash Chapter 5 Prime Time
class 6 Mathematics Textbook Chapter 5 question answer
To make 8560 divisible by 8, the last two digits must form a number divisible by 8. Replace 60 with 56, creating 8556. Dividing 8556 ÷ 8 = 1069 confirms divisibility without remainder. This adjustment ensures the number meets the criteria, as divisibility by 8 depends on the last two digits forming a valid multiple of 8.
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8556 isn’t completely divisible by 8
8556/ 8 =1,069.5 not 1068.
You have to subtract 8 from 8560 to get a number completely divisible by 8 .either it would be 8568 or 8552.
In this case , it would be 8552 since you have to change last two digits
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