Changing the last two digits to 56 makes the number divisible by 8. For example, 8556 is a multiple of 8 because 8556 ÷ 8 = 1069 with no remainder.
Class 6 NCERT Ganita Prakash Chapter 5 Prime Time
class 6 Mathematics Textbook Chapter 5 question answer
To make 8560 divisible by 8, the last two digits must form a number divisible by 8. Replace 60 with 56, creating 8556. Dividing 8556 ÷ 8 = 1069 confirms divisibility without remainder. This adjustment ensures the number meets the criteria, as divisibility by 8 depends on the last two digits forming a valid multiple of 8.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/