Can you please provide the explanation video of this given question for better understanding.
NCERT class 10 Chapter 12
Page No. 238
Exercise 12.3
Question No. 16
Calculate the area of the designed region in Figure common between the two quadrants of circles of radius 8 cm each.
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Area of sector DAFC
= 90°/360° × πr² = 1/4 × π(8)²
= 1/4 × 22/7 × 8 × 8 = 352/7 cm²
Area of triangle ADC
= 1/2 × DC × AD
= 1/2 × 8 × 8
= 32 cm²
Area of segment = Area of sector DAFC – Area of triangle ADC
= (352/7 – 32) cm² = ((352 – 224)/7) cm² = (128/7) cm²
Area of shaded region = Area of two segments
= 2 × (128/7) cm² = 256/7 cm²
Here is the video explanation 🤗👇