Class 12 Physics
CBSE and UP Board
Alternating Current
Chapter-7 Exercise 7.2
NCERT Solutions for Class 12 Physics Chapter 7 Question 2
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Ans (a).
Peak voltage of the ac supply, Vo = 300 Vrms voltage is given as:
V = V0/√ 2 = 300/√ 2 = 212.1 V
Ans (b).
The rms value of current is given as: I = 10 A
Now, peak current is given as: I0 = √ 2 I = √ 2 x 10 = 14.1 A