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Ashok0210
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Asked: 2021-03-05T06:06:55+00:00 In:

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m³ s⁻¹. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms⁻²).

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Class 12 Physics
CBSE and UP Board
Alternating Current
Chapter-7 Exercise 7.24
Additional Exercise

NCERT Solutions for Class 12 Physics Chapter 7 Question 24

2020-2021cbse and up boardclass 12 chapter-7 physicsclass 12 physicsncert class 12 alternating current
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      Height of water pressure head, h = 300 m
      Volume of water flow per second, V = 100 m3/s
      Efficiency of turbine generator, n = 60% = 0.6
      Acceleration due to gravity, g = 9.8 m/s2
      Density of water, ρ = 103 kg/m3
      Electric power available from the plant = η x hρgV
      = 0.6 x 300 x 103 x 9.8 x 100 = 176.4 x 106 W = 176.4 MW

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