A wire in the form of a circular loop, of one turn carrying a current, produces magnetic induction B at the centre. If the same wire is looped into a coil of two turns and carries the same current, the new value of magnetic induction at the centre is
The correct answer is (C) 4B.
Magnetic induction at the center of a circular coil with n turns is given by B′ = n² B. For two turns (n = 2), the magnetic induction becomes B′ = 2²B = 4B, quadrupling the original value.
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Magnetic induction at the center of a single-turn circular loop carrying current I is given by:
B = μ0I/2R
When the wire is looped into two turns, the number of turns
n = 2 and the magnetic induction becomes:
B’ = n² B = 2²B = 4B
Thus, the new magnetic induction at the center is 4B.
Answer: (C) 4B.
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