A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah. (ii) the cost of cementing the floor of the verandah at the rate of ₹200 per m².

(i) The length of room = 5.5 m and width of the room = 4 m
The length of room with verandah = 5.5 + 2.25 + 2.25 = 10 m
The width of room with verandah = 4 + 2.25 + 2.25 = 8.5 m
Area of verandah
= Area of room with verandah – Area of room without verandah
= Area of ABCD – Area of EFGH
= (AB x AD) – (EF x EH)
= (10 x 8.5) – (5.5 x 4)
= 85 – 22
= 63 m²
(ii) The cost of cementing 1 m2 the floor of verandah = ₹ 200
The cost of cementing 63 m2 the floor of verandah = 200 x 63 = ₹12,600

Class 7 Maths Chapter 11 Exercise 11.4

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