A uniform electric field of 100 N/C exists in vertically upward direction. The decrease in electric potential as one goes up through a height of 5 cm is
The potential difference in a uniform electric field is given by V = E × d. Given E = 100 N/C and d = 5 cm = 0.05 m, we get V = 5 V. Thus, the correct answer is (c) 5 V.
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.
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The potential difference (ΔV) in a uniform electric field is given by:
ΔV = − E⋅d.
where:
E=100N/C (electric field strength)
d = 5 cm = 0.05 m (displacement in the field direction)
ΔV = −(100×0.05)
ΔV = −5 V
Since the question asks for the decrease in potential, the answer is: (c) 5 V
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