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A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60°. From another point 20 m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is 30° Find the height of the tower and the width of the canal.

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NCERT Solutions for Class 10 Maths Chapter 9
Important NCERT Questions
SOME APPLICAT IONS OF TRIGONOMETRY
(Height and Distance)
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 9.1
Page No:204
Questions No:11

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2 Answers

  1. Get here all the solutions of class 10 Maths Exercise 9.1

    NCERT Solutions for class 10 Maths Exercise 9.1 all questions in Hindi Medium

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  2. Let AB is TV tower and BC is width of the canal. In ΔABC,
    AB/BC = tan 60° ⇒ AB/BC = √3
    ⇒ BC = AB√3
    In ΔABD,
    AB/BD = tan 30° ⇒ AB/(BC+CD) = 1/√3
    ⇒ AB/(AB/√3+CD) = 1/√3 [Putting the value of BC]
    ⇒ AB√3/(AB + 20√3) = 1/√3 ⇒ 3AB = AB + 20√3 ⇒ 2AB = 20√3 ⇒AB = 10√3
    Therefore, BC = AB/√3 = 10√3/√3= 10
    Hence, the height of the tower is 10√3m and the width of tower is 10m.

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