Let speed be s and time t. The conditions give (s + 6)(t − 6) = st and (s − 4)(t + 6) = st, simplifying to t − s = 6 and 3s − 2t = 12. Solving yields s = 24 km/h and distance d = 720 km.
Class 9 Maths (Ganita Manjari part two) Chapter 13 questions answer
Class 9 Maths (Ganita Manjari part two) Two Variables, One Line Question Answer
Let uniform speed be s km/h and scheduled time be t hours, with distance d = st. From (s + 6)(t − 6) = st, expansion gives −6s + 6t − 36 = 0 or t − s = 6. From (s − 4)(t + 6) = st, expansion gives 6s − 4t − 24 = 0 or 3s − 2t = 12. Substituting t = s + 6 into the second equation yields s = 24 km/h, t = 30 hours and distance d = 24 × 30 = 720 km.
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