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A source produces a sound wave of wavelength 3.44 m. If the wave travels with a speed of 344 m s⁻¹ find its time period.

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Using speed equals wavelength divided by time period, dividing 3.44 meters by 344 meters per second gives a frequency of 100 Hz, yielding a wave time period of 0.01 seconds.

Class 9 Science Exploration New Book All Chapter Solution

Revise, Reflect, Refine Chapter 10 Sound Waves Question Answer

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  1. The frequency of the wave is calculated by dividing speed by wavelength: 344 meters per second divided by 3.44 meters equals 100 Hz. Since the time period is the inverse of frequency, dividing 1 by 100 Hz gives 0.01 seconds. Thus, the time taken for one complete density oscillation at any fixed point in the medium is 0.01 seconds.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 10 Sound Waves Characteristics and Applications Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-10/

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