A solenoid has 1000 turns per metre length. If current of 5 A is flowing through it, then magnetic field inside the solenoid is
The correct answer is (C) 4π × 10⁻³T.
The magnetic field inside a solenoid is given by
B = μ0nI, where μ0 = 4π × 10⁻⁷T⋅ m/A,n = 1000 turns/m and I = 5A, giving
B = 4π × 10⁻³T.
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