Rotating forms a cone with height 8 cm, radius 6 cm and slant height 10 cm. Volume is (1/3)π(6²)(8) = 96π ≈ 301.71 cm³. Curved surface area is π(6)(10) = 60π ≈ 188.57 cm².
Cbse Class 9 Maths Ganita Manjari Part 2 Solutions
Class 9 maths ganita manjari part 2 chapter 14 question answer
Rotating the right triangle about the 8 cm side generates a right circular cone having height h = 8 cm, base radius r = 6 cm and slant height l = 10 cm.
Volume is V = (1/3)πr²h = (1/3)π × 6² × 8 = 96π ≈ 301.71 cm³.
Curved surface area is CSA = πrl = π × 6 × 10 = 60π ≈ 188.57 cm².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/