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A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?

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NCERT Solutions for Class 8 Mathematics Chapter 2
Important NCERT Questions
Linear Equations in one Variable Chapter 2 Exercise 2.4
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 2

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2 Answers

  1. Let the smaller positive number be x, making the larger number 5x. When 21 is added to both, the new expressions become x + 21 and 5x + 21. According to the problem statement, the larger new number becomes twice the smaller one. This sets up the equation 5x + 21 = 2(x + 21). Expanding gives 5x + 21 = 2x + 42. Simplifying leads to 3x = 21, so x = 7 and 5x = 35.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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  2. Let another number be x.
    Then positive number = 5x
    According to the question, 5x+21=2(x+21)
    ⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21
    ⇒ x=21/3=7
    Hence another number = 7 and positive number = 5×7=35

    Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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