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A particle covers 20m in the first 2 seconds of its motion from rest under uniform acceleration. What is the magnitude of its acceleration?

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Poll Results

100%5m/s^2 ( 1 voter )
0%10m/s^2
0%2.5m/s^2
0%20m/s^2
Based On 1 Vote

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This question involves the application of the second equation of motion to calculate the acceleration of a particle when its displacement, initial velocity and time are given.

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1 Answer

  1. The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s:
    20 = 0 +1/2a(2²)
    20 = 2a
    a = 10 m/s².

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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