Given u = 28 m s⁻¹, v = 0 and s = 98 m. Using v² = u² + 2as, we get a = −4 m s⁻². Time taken, t = (v − u)/a = 7 s.
A motorbike moving with initial velocity 28 m s⁻¹ and constant acceleration stops after travelling 98 m. Find the acceleration of the motorbike and the time taken to come to a stop.
Share