A long straight wire in the horizontal plane carries a current of 15 A in north to south direction. The magnitude and direction of magnetic field at a point 2.5 m east of the wire respectively are :
The correct answer is (A) 1.2 µT, vertically upward.
Using the Biot-Savart law, the magnetic field at a distance of 2.5 m from a current of 15 A is B = μ0l/2πr.
The direction, by the right-hand rule, is vertically upward.
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The magnetic field around a long, straight current-carrying wire is given by:
B = μ0I/2πr
Substituting values:
B = 4π × 10⁻⁷ × 15/2π × 2.5 = 1.2 × 10⁻⁶ T = 1.2 μT
Using the right-hand thumb rule, the magnetic field at a point east of the wire points vertically downward.
Answer: (A) 1.2 µT, vertically downward.
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