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Home/ Questions/Q 968
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Umangi Grover
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Umangi Grover
Asked: October 20, 20202020-10-20T11:55:03+00:00 2020-10-20T11:55:03+00:00In: Class 10

A hot plate of an electric oven connected to a 220 V line has two resistance coils A and B, each of 24 ohm resistance, which may be used separately, in series, or in parallel. What are the currents in the three cases?

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NCERT Solution for Class 10 Science Chapter 12
Electricity
NCERT Books for Session 2020-2021
CBSE Board and UP Board
Exercises Questions
Page No-221
Questions No-13

2020-2021cbsechapter 12class10electricityncertscience
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    1. Consult From physics
      2020-12-06T06:44:04+00:00Added an answer on December 6, 2020 at 6:44 am

      Given that: Potential difference V = 220 V and resistance of each coil R = 24 Ω
      When the coil is used separately, the current in the coil is given by
      𝐼=𝑉𝑅=220/24=55/6=9.16 𝐴
      When the two coils are connected in series, the net resistance is given by
      𝑅=𝑅1+𝑅2=24 Ω+24 Ω=48 Ω
      Now, the current in the coil is given by
      𝐼=𝑉𝑅=220/48=55/12=4.58 𝐴
      When the two coils are connected in parallel, the net resistance is given by 1/𝑅=1/24+1/24=2/24=1/12 ⟹𝑅=12 Ω
      Now, the current in the coil is given by
      𝐼=𝑉𝑅=22012=553=18.33 𝐴

      For more answers visit to website:
      https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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    2. Best Answer
      Praveen
      2021-02-03T09:28:32+00:00Added an answer on February 3, 2021 at 9:28 am

      Supply voltage, V = 220 V

      Resistance of one coil, R = 24 Ω

      (i) Coils are used separately

      According to Ohm’s law,

      V = I1R1

      Where,

      I1 is the current flowing through the coil

      𝐼=𝑉𝑅=220/24=55/6=9.16 𝐴

       

      Therefore, 9.16 A current will flow through the coil when used separately.

      (ii) Coils are connected in series

      Total resistance, R2 = 24 Ω + 24 Ω = 48 Ω

      According to Ohm’s law,

      V = I2R2

      Where,

      I2 is the current flowing through the series circuit

      𝐼=𝑉𝑅=220/48=55/12=4.58 𝐴

       

      Therefore, 4.58 A current will flow through the circuit when the coils are connected in series.

      (iii) Coils are connected in parallel

      Total resistance, R3 is given as

      1/𝑅=1/24+1/24=2/24=1/12 ⟹𝑅=12 Ω

       

      According to Ohm’s law,

      V = I3R3

      Where,

      I3 is the current flowing through the circuit

      𝐼=𝑉𝑅=22012=553=18.33 𝐴

       

      Therefore, 18.33 A current will flow through the circuit when coils are connected in parallel.

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