A hollow sphere of internal and external diameter 4 cm and 8cm respectively is melted into a cone of base diameter 8 cm. The height of the cone is
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Volume of hollow sphere:
V_sphere = (4/3)π(R³ – r³) = (4/3)π(4³ – 2³) = (224/3)π.
Volume of cone:
V_cone = (1/3)πr²h = (1/3)π(4²)h.
Equating volumes:
(224/3)π = (1/3)π(16)h → 224 = 16h → h = 14 cm.
This question related to Chapter 12 Mathematics Class 10th NCERT. From the Chapter 12. Surface Areas and Volumes. Give answer according to your understanding.
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