A current of 5 A is flowing from east to west In a long straight wire kept on a horizontal table. The magnetic field developed at a distance of 10 cm due south on the table is :
The magnetic field due to a straight current-carrying wire is given by
B = μ0I/2πr . Substituting μ0 = 4π × 10⁻⁷ , I = 5 A and r = 0.1 m, B = 1 × 10⁻⁵ T. Using the right-hand rule, it acts upwards. Answer: (B).
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The magnetic field around a long, straight current-carrying wire is given by:
B = μ0I/2πr
Substituting values:
B = 4π × 10⁻⁷ × 5/2π × 0.10 = 1 × 10⁻⁵ T
Using the right-hand thumb rule, the magnetic field at a point due south acts upward. Therefore, the correct answer is:
(B) 1 × 10⁻⁵ T acting upwards.
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