Kriti
  • 0

A coconut of mass 1.5 kg falls from the top of a coconut tree onto the wet sand on a beach. The height of the tree is 10 m. On impact, the coconut comes to rest by making a depression in the sand. (i) Calculate the velocity of the coconut just before it hits the sand. (ii) Assume that the average resistive force of sand is 3000 N and all of the coconut’s energy is used to create the depression in the sand. Calculate the depth of the depression the coconut makes in the sand. Assume g = 10 m s-2.

  • 0

The impact velocity is 14.14 m s-1, derived from square root of two g h. Total kinetic energy equals 150 J, which divided by 3000 N resistive force gives a sand depression depth of 0.05 m.

Share

1 Answer

  1. Using conservation of energy, the velocity before impact equals square root of two times g times h, which is square root of 200, giving 14.14 m s-1. The kinetic energy on impact equals initial potential energy m g h, totaling 150 J. Equating this energy to work done against sand resistance, 150 J divided by 3000 N yields a depression depth of 0.05 m or 5 cm.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 7 Work, Energy and Simple Machines Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-6/

    • 0
Leave an answer

Leave an answer

Browse