Asked: 2025-03-07T04:48:27+00:002025-03-07T04:48:27+00:00In: Class 12 Physics
A car battery is charge by a 12 V supply and energy stored it is 7.20 10 J. The charge passed throuh the battery is:
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The energy stored in the battery is given as 7.20 × 10⁴ J, and the charging voltage is 12 V. Using the relation:
E = QV
where:
. E = Energy (7.20 × 10⁴ J)
. Q = Charge (to be found)
. V = Voltage (12 V)
Rearranging the equation for Q:
Q = E/V = 7.20 ×10⁴/12
Q = 6.0 × 10⁴C
thus, the correct answer is (a) 6.0 × 10⁴C.
The energy stored in the battery is given as 7.20 × 10⁴ J, and the supply voltage is 12 V. Using the formula Energy (E) = Charge (Q) × Voltage (V), we find:
The energy stored in the battery is given as 7.20 × 10⁴ J, and the supply voltage is 12 V. Using the formula Energy (E) = Charge (Q) × Voltage (V), we find:
Q = E/V = (7.20 × 10⁴ J) / (12 V) = 6.0 × 10⁴ C
Thus, the correct answer is (a) 6.0 × 10⁴ C.
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