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A bar magnet AB with magnetic moment M is cut into two equal parts perpendicular to its axis. One part is kept over the other so that end B is exactly over A. What will be the magnetic moment of the combination so formed ?
The correct answer is: (C) M. When a bar magnet is cut into two equal parts perpendicular to its axis, each piece retains the same magnetic moment M/2. Placing one over the other with opposite poles touching (B over A) aligns their moments in the same direction, so total moment = M/2 + M/2 = M.
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When a bar magnet of magnetic moment
M is cut into two equal parts perpendicular to its length, each part gets half the length but retains the same pole strength. Hence, the magnetic moment of each piece becomes M/2. Placing one over the other with opposite poles touching (B over A), their magnetic moments oppose and cancel out. Answer: (A) Zero.
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