2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.

Given that : Volume of cube = 64 cm³
⇒ (Side)³ = 64 cm³ ⇒ Side = 4 cm
The sides of cuboids formed by joining the cubes are 4 cm, 4 cm and 8 cm.
Surface area of resulting cuboid
= 2 (Ib + bh +hl)
=2(4×4 + 4×8 +4×8)cm²
= 2(16+32+32)cm²
= 2(80) cm²
= 160 cm²
Hence, the surface area of the resulting cuboid 160 cm².