Given P = I² R₃, substituting values: 6 = (2.0)² R₃ ⟹ R₃ = 1.5Ω Voltage across R₃, V₃ = IR₃ = 2.0 ×1.5 = 3V. Answer: (c) 3V. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions ...
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The wire is divided into two equal semicircles, each with resistance R. These are in parallel, so the effective resistance is: 1/Reff = 1/R + 1/R Thus, Reff = R/2. Answer: (b) R/2. Class 12th Science Physics NCERT MCQ Questions NCERT ...
Resistance is given by R = p L/A . Given La/Lb = 1/2 and da/db = 2/3, so Aa/Ab = 2/3 2 = 4/g. thus, Ra/Rb = (1/2)/(4g) = 9/8. Since V ∝ R in series, Va/Vb = Ra/Rb = ...
For balance, p/Q = R/Seq . Given S = 3Ω, let shunt resistance be x. Using Seq = 3x/3+x = 2Ω. solving gives x = 2Ω. Answer: (b) 2Ω. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions ...
In a potentiometer, emf ∝ balancing length. Given v/1.5V = U3/Lx , solving for Lx gives Lx = L/3. Answer: (c) l/3. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions Session 2024-2025.