The minor sector area is (60/360) x π x r² = (1/6)πr². The triangle formed is equilateral with side r, giving area (√3/4)r². Subtracting yields segment area (1/6)πr² – (√3/4)r² = πr²(1/6 – √3/(4π)).
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Minor sector is (60/360) x 3.14 x 15² = 117.75 cm². Equilateral triangle area is (√3/4) x 15² = 97.31 cm². Minor segment is 117.75 – 97.31 = 20.44 cm². Major segment is 706.5 – 20.44 = 686.06 cm².
Since CQ || PD, triangles DPQ and DPC share base PD and parallel lines, giving Area(ΔDPQ) = Area(ΔDPC). Thus, Area(ΔBPQ) = Area(ΔBPD) + Area(ΔDPQ) = Area(ΔBPD) + Area(ΔDPC) = Area(ΔBDC) = (1/2) x Area(ΔABC).
Diagonal PR divides parallelogram PQRS into equal triangles PSR and PQR. Similarly, triangles OSR and OQR share base and equal heights, making their areas equal. Subtracting gives area(ΔPSO) = area(ΔPQO).
Ratio parts sum to 3 + 5 + 7 = 15, giving sides 60 m, 100 m, and 140 m with semi-perimeter s = 150 m. Area = √(150 x 90 x 50 x 10) = 1500√3 m² (approx 2598.08 ...