For a cube of side a, total surface area is S = 6a², which gives a = √(S/6). Since volume is V = a³, substituting a gives V = (S/6)³ᐟ² or S√S/(6√6). Cbse Class 9 Maths Ganita Manjari Part 2 Solutions Class ...
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For a cube of side a, total surface area is S = 6a², which gives a = √(S/6). Since volume is V = a³, substituting a gives V = (S/6)³ᐟ² or S√S/(6√6). Cbse Class 9 Maths Ganita Manjari Part 2 Solutions Class ...