Inverting a second congruent trapezium alongside the first forms a parallelogram of base (a + b) and height h. Its area is (a + b)h, so one trapezium has area (1/2)(a + b)h.
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Inverting a second congruent trapezium alongside the first forms a parallelogram of base (a + b) and height h. Its area is (a + b)h, so one trapezium has area (1/2)(a + b)h.