A regular hexagon consists of 6 equilateral triangles of side r, giving area 6 x (√3/4)r² = (3√3/2)r². Dividing by circle area πr² gives (3√3) / (2π) ≈ 0.827, which is twice Question 8’s ratio because its area is double.
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A regular hexagon consists of 6 equilateral triangles of side r, giving area 6 x (√3/4)r² = (3√3/2)r². Dividing by circle area πr² gives (3√3) / (2π) ≈ 0.827, which is twice Question 8’s ratio because its area is double.