The smallest number is 2520 ÷ 7 = 360. The least common multiple (LCM) of numbers 1 to 10 is 2520. Excluding 7, dividing 2520 by 7 gives the smallest valid number, 360. Class 6 Mathematics Ganita Prakash Prime Time Class 6 ...
Discussion Forum Latest Questions
Changing the last two digits to 56 makes the number divisible by 8. For example, 8556 is a multiple of 8 because 8556 ÷ 8 = 1069 with no remainder. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics ...
The game says ‘idli-vada’ for common multiples of 3 and 5. These are: 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Thus, the 10th instance is at 150. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics Chapter ...
Twin primes between 1 and 100 include (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), and (71, 73). These pairs differ by exactly 2. Class 6 Mathematics Chapter 5 Prime Time question answer Class 6 NCERT ...
The number is 2520 ÷ 7 = 360. The least common multiple (LCM) of 1 to 10 is 2520. Excluding 7, we divide by 7 to obtain 360, the smallest valid number. class 6 Mathematics Textbook Chapter 5 question answer class 6 ...