There are 15 prime numbers between 1 and 50. These are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics Chapter 5 Prime Time ...
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42 is not divisible by 12. The prime factorization of 42 is 2 × 3 × 7, and 12 is 2² × 3. The missing 2² in 42 prevents divisibility. Class 6 Mathematics Chapter 5 Prime Time question answer Class 6 NCERT ...
The smallest number with three different prime factors is 2 × 3 × 5 = 30. These are the smallest primes, and their product yields the smallest composite number meeting the condition. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics ...
Multiples are numbers obtained by multiplying a given number by integers. For example, the multiples of 4 are 4, 8, 12, 16, and so on. They represent repeated additions of the original number. Multiples of 3: 102, 105, 108, …, ...
This statement is sometimes true. For example, 2 + 2 = 4 (a multiple of 4), but 2 + 6 = 8 (not always divisible by 4). It depends on the specific even numbers. Class 6 Mathematics Ganita Prakash Prime Time Class ...
The smallest number is 2520 ÷ 7 = 360. The least common multiple (LCM) of numbers 1 to 10 is 2520. Excluding 7, dividing 2520 by 7 gives the smallest valid number, 360. Class 6 Mathematics Ganita Prakash Prime Time Class 6 ...
Changing the last two digits to 56 makes the number divisible by 8. For example, 8556 is a multiple of 8 because 8556 ÷ 8 = 1069 with no remainder. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics ...
The game says ‘idli-vada’ for common multiples of 3 and 5. These are: 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Thus, the 10th instance is at 150. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics Chapter ...
Twin primes between 1 and 100 include (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), and (71, 73). These pairs differ by exactly 2. Class 6 Mathematics Chapter 5 Prime Time question answer Class 6 NCERT ...
The number is 2520 ÷ 7 = 360. The least common multiple (LCM) of 1 to 10 is 2520. Excluding 7, we divide by 7 to obtain 360, the smallest valid number. class 6 Mathematics Textbook Chapter 5 question answer class 6 ...