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Asked: October 20, 2020In: Class 10

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

NCERT Solution for Class 10 Science Chapter 12 Electricity NCERT Books for Session 2022-2023 CBSE Board and UP Board Intext Questions Page No-218 Questions No-2

Sadhika Gujral

Asked: October 20, 2020In: Class 10

An electric iron of resistance 20 ohm takes a current of 5 A. Calculate the heat developed in 30 s.

NCERT Solution for Class 10 Science Chapter 12 Electricity NCERT Books for Session 2022-2023 CBSE Board and UP Board Intext Questions Page No-218 Questions No-3

Dev Kumar

Asked: October 20, 2020In: Class 10

What determines the rate at which energy is delivered by a current?

NCERT Solution for Class 10 Science Chapter 12 Electricity NCERT Books for Session 2022-2023 CBSE Board and UP Board Intext Questions Page No-220 Questions No-1

Dev Kumar

Asked: October 20, 2020In: Class 10

An electric motor takes 5 A from a 220 V line. Determine the power of the motor and the energy consumed in 2 h.

NCERT Solution for Class 10 Science Chapter 12 Electricity NCERT Books for Session 2022-2023 CBSE Board and UP Board Intext Questions Page No-220 Questions No-2

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Dev Kumar

Asked: October 20, 2020In: Class 10

A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R ‘, then the ratio R/R ‘ is –

NCERT Solution for Class 10 Science Chapter 12 Electricity NCERT Books for Session 2022-2023 CBSE Board and UP Board Exercises Questions Page No-221 Questions No-1

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

An electric iron of resistance 20 ohm takes a current of 5 A. Calculate the heat developed in 30 s.

What determines the rate at which energy is delivered by a current?

An electric motor takes 5 A from a 220 V line. Determine the power of the motor and the energy consumed in 2 h.

A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R ‘, then the ratio R/R ‘ is –

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