For (a + b)(a – b), remove corner square b² from square a²; rearrange the remaining L-shape into rectangle (a + b) by (a – b). For (a + b + c)², divide a square into 9 blocks yielding a² ...
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Kriti
Asked: In: Class 9 Maths
In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².
Kriti
Asked: In: Class 9 Maths
Circumference 2 x (22/7) x r = 44 yields radius r = 7 cm. A quadrant has angle 90°, so its area is (1/4) x π x r² = (1/4) x (22/7) x 7² = 77/2 = 38.5 cm².
Kriti
Asked: In: Class 9 Maths
Midpoints cut each corner triangle’s area to 1/4 of its diagonal triangle. Summing opposite corner triangles removes 1/4 + 1/4 = 1/2 of the total 4-gon area, leaving exactly half for the inner Varignon parallelogram.
Sonal Chauhan
Asked: In: Class 9 Maths
Diagonal PR divides parallelogram PQRS into equal triangles PSR and PQR. Similarly, triangles OSR and OQR share base and equal heights, making their areas equal. Subtracting gives area(ΔPSO) = area(ΔPQO).
chapter 6 measuring space: perimeter and area question answerclass 9 ganita manjari chapter 6 measuring space: perimeter and area solutionsimportant questions from chapter 6 measuring space: perimeter and areancert class 9 ganita manjari chapter 6 question answerparallelogram pqrsprove that the areas of triangles pso and pqo are equal