The smallest number is 2 × 3² × 7 = 126. Multiplying these primes in increasing order ensures the smallest number containing exactly the specified prime factors. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics Textbook Chapter 5 ...
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This statement is always true. The sum of two odd numbers is always even, and when two odd numbers are added, their remainders modulo 4 sum to 4, ensuring divisibility by 4. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics ...
A number is divisible by 4 if the number formed by its last two digits is divisible by 4. For example, 132 is divisible by 4 because 32 (the last two digits) is divisible by 4. Between 1730 and 1740: ...
Remainders obtained when each of the following numbers is divided by 10, 5, 2. 78: Rem. by 10: 8, by 5: 3, by 2: 0 99: Rem. by 10: 9, by 5: 4, by 2: 1 173: Rem. by 10: 3, by 5: ...