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Ashok0210

Asked: February 24, 2021In: Class 12 Physics

Answer the following questions: (a) Why does a paramagnetic sample display greater magnetisation (for the same magnetising field) when cooled? (b) Why is diamagnetism, in contrast, almost independent of temperature? (c) If a toroid uses bismuth for its core, will the field in the core be (slightly) greater or (slightly) less than when the core is empty? (d) Is the permeability of a ferromagnetic material independent of the magnetic field? If not, is it more for lower or higher fields? (e) Magnetic field lines are always nearly normal to the surface of a ferromagnet at every point. (This fact is analogous to the static electric field lines being normal to the surface of a conductor at every point.) Why? (f ) Would the maximum possible magnetisation of a paramagnetic sample be of the same order of magnitude as the magnetisation of a ferromagnet?

Class 12 Physics CBSE and UP Board Magnetism and Matter Chapter-5 Exercise 5.16 Additional Exercise NCERT Solutions for Class 12 Physics Chapter 5 Question 16

Ashok0210

Asked: February 24, 2021In: Class 12 Physics

A short bar magnet of magnetic moment 5.25 × 10⁻² J T⁻¹ is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45º with earth’s field on (a) its normal bisector and (b) its axis. Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.

Class 12 Physics CBSE and UP Board Magnetism and Matter Chapter-5 Exercise 5.15 NCERT Solutions for Class 12 Physics Chapter 5 Question 15

Ashok0210

Asked: February 24, 2021In: Class 12 Physics

If the bar magnet in exercise 5.13 is turned around by 180º, where will the new null points be located?

Class 12 Physics CBSE and UP Board Magnetism and Matter Chapter-5 Exercise 5.14 NCERT Solutions for Class 12 Physics Chapter 5 Question 14

Ashok0210

Asked: February 24, 2021In: Class 12 Physics

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)

Class 12 Physics CBSE and UP Board Magnetism and Matter Chapter-5 Exercise 5.13 NCERT Solutions for Class 12 Physics Chapter 5 Question 13

Ashok0210

Asked: February 24, 2021In: Class 12 Physics

A short bar magnet has a magnetic moment of 0.48 J T⁻¹. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.

Class 12 Physics CBSE and UP Board Magnetism and Matter Chapter-5 Exercise 5.12 NCERT Solutions for Class 12 Physics Chapter 5 Question 12

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If the bar magnet in exercise 5.13 is turned around by 180º, where will the new null points be located?

A short bar magnet has a magnetic moment of 0.48 J T⁻¹. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.

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